Question

Show that 3z 10 is a factor of 9z3 - 27z2 - 100z 300. Find also the other factors.

Answer 1

Answer:

$9z^3 - 27z^2 - 100z+ 300=(3z-10)(3z+10)(z-3)$.

other factors are 3z+10 and z-3

Step-by-step explanation:

Show that (3z -10) is a factor of $9z^3 - 27z^2 - 100z+ 300$.

Find also the other factors.

Formula used:

$a^2-b^2=(a+b)(a-b)$

Given:

$9z^3 - 27z^2 - 100z+ 300$.

$=9z^2(z-3)-100(z- 3)$.

$=(9z^2-100)(z-3)$.

$=((3z)^2-(10)^2)(z-3)$.

$=(3z-10)(3z+10)(z-3)$ (using $a^2-b^2=(a+b)(a-b)$)

Hence (3z-10) is a factor

Answer 2

stream all to well!! taylors version from the vault <3