Question

Show that 4√2 is an irrational number​

Answer 1

let 4√2 be rational no. then,

4√2= $\frac{a}{b}$

where a & b are positive integer

and b≠0

4√2=$\frac{a}{b}$

=> √2= $\frac{a}{4b}$

$\frac{integer}{integer} = rational$

=> And we know that √2 is irrational

irrational≠rational

$\therefore$Our supposition is wrong...

and

4√2 is irrational!

$<b><marquee>HENCE PROVED!</marquee></b>$