Question

show that 4n can never end with digital zero for any natural number

Answer 1

For a digit to end with 0 it should have both 2 and 5 as a factor.

 

After factorizing 4 you get 4= 2*2

                                            =2^2

Therefore 4^n= 2^2*n

 

It only has 2 as a factor and 5 is missing.

Hence any number of the form 4^n (where n is any natural number) cannot end with the digit zero.

 

Hope This Helps :)

Answer 2

bcz in prime facrorisation of 4n we find that it does not end with the digit 5 or 0.
so therefore 4n cannot end wid digit 0