Question

Show that A (6, 4); B (5,-2) and C (7,-2) are the vertices of an Isosceles triangle.​

Answer 1

Answer:

By applying distance formula in sides AB and BC

Step-by-step explanation:

you will get the answer

Answer 2

Answer:

hey mate here's your answer

Step-by-step explanation:

Using distance formula

Distance = √(x₂-x₁)² + (y₂-y₁)²

AB² = (6-5)² + (4+2)²

AB² = 37

BC² = (5-7)² + (-2+2)²

BC² = 5

AC² = (6-7) ²+(4+2)²

AC² = 37

Since AB² =AC², so AB =AC

If in a triangle two sides are equal then the triangle is isosceles

I helped you now you help me by making this answer as brainliest