Question

show that any positve odd integer is of the form 4q+1or 4q+3, where q is some whole no.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Let a = any positive integer

b = 4

By Euclid Division Lemma,

a = b×q+r. (0≤r<4).

(i)r=0

a=4q

a=2(2q)

(ii)r= 1

a=4q +1

(iii)r=2

a=4q+2

a=2(2q+1)

(iv)r=3

a=4q+3

(i) and (iii) are even because they are divisible by 2 and 4q+1 and 4q+3 are odd.

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