Show that
Cos2A - Sin2A = - 7/13
Given TanA = 2/3
DO NOT CALCULATE THE VALUE OF A
Answers
Answered by
0
Answer:-7/13
Step-by-step explanation:
Given that, TanA=2/3=p/b
Now, Cos2A-Sin2A=?
Cos2A=(1-tan^2A)/(1+tan^2A)
={1-(4/9)}/{1+(4/9)}
=(5/9)/(13/9)=5/13
Now Sin2A=2tanA/(1+tan^2A)
=2×(2/3)/{1+(4/9)}
=(4/3)/(13/9)=12/13
Now Cos2A-Sin2A=(5/13)-(12/13)=-7/13
Similar questions