show that every positive odd integer is of the form 6n+1 , 6n+3, 6n+5.
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(1).........a=bq+r
r=o,1,2,3,4,5
a=6q+6
2 (3q)
a=6q+2
(2)........a=2 (3q+1)
a=6q+4
(3)........a=6q+r
a=2 (3q+2)
those number divisible by 2
so,that no will be positive number
hayajune22:
thank you
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