show that if :R- {7÷5} _{3÷5}is defined by f(x)=3x+4÷5x-7& g:r-{3÷5}_{7÷5} defined by g(x)=7x+4÷5x-3 then find f invertible
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R- {7÷5} _{3÷5}is defined by f(x)=3x+4÷5x-7& g:r-{3÷5}_{7÷5} defined by g(x)=7x+4÷5x-3
f=1.1111
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