Show that one ampere is equivalent to a flow of 6.25*10^18 elementary charges
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t=1s, total charge=i×t,. 1×1=1c,. charge on electron=1.6×10^-19 . therefore no of electron =total charge÷charge on electron , 1c ÷1.6×10^-19 = 6.25× 10^-18
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