show that p square will leave remainder 1 when devided by 8, if p is an odd positive integer
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let us take p=3 then
p^2 = 9 => 9/8 =>1+1/8
we will get remainder as 1
let us take p=5 then
p^2=25 => 25/8 => 3+1/8
we will get remainder as 1
and so on............
p^2 = 9 => 9/8 =>1+1/8
we will get remainder as 1
let us take p=5 then
p^2=25 => 25/8 => 3+1/8
we will get remainder as 1
and so on............
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