Math, asked by saaim011, 1 year ago

show that tan3A.tan2A.tanA=tan3A-tan2A-tanA

Answers

Answered by mansigupta23
2
here is your answer above the attachment hope its helpful
Attachments:
Answered by ajeshrai
2
tan(3A-2A)=tan3A-tan2A/1+tan3A.tan2A

tanA=tan3A-tan2A/1+tan3A.tan2A

tanA+tanA.tan2A.tan3A=tan3A-tan2A

tanA.tan2A.tan3A=tan3A-tan2A-tanA....







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