Question

Show that the equaion
x
${x}^{2} + y { }^{2} - 6x + 4y - 36 = 0$

represents a circle. Also, find its centre and radius​

Answer 1

Answer:

r=7  and centre(3,-2)

Step-by-step explanation:

x²-6x+9+y²+4y+4-36-13=0

(x-3)²+(y+2)²=49=7²

(x-3)²+(y+2)²=7²

this is a circle with radius 7 unit

and centre(3,-2))