Show that the matrix b'ab is symmetric or skew symmetric according to as a
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Answer:
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The key things to know here are:
1) (xy)' = y'x' [ the transpose of a product is the product of the transposes with the order of multiplication reversed ]
2) (x')' = x [ the transpose of the transpose is back to where we started ]
3) x is symmetric means x' = x
4) x is skew symmetric means x' = -x
Because of (1) above, the transpose of b'ab is
5) (b'ab)' = b'a'(b')' = b'a'b
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a is symmetric
<=> a' = a [ see (3) ]
<=> b'a'b = b'ab [ do the same to both sides ]
<=> (b'ab)' = b'ab [ see (5) ]
<=> b'ab is symmetric [ see (3) ]
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a is skew symmetric
<=> a' = -a [ see (4) ]
<=> b'a'b = -b'ab [ do the same to both sides ]
<=> (b'ab)' = -b'ab [ see (5) ]
<=> b'ab is skew symmetric [ see (4) ]