Question

What is the ph of solution obtained by mixing 50ml 0.4n hcl and 50ml 0.2n naoh

Answer 1

The pH of the solution is 1.

Explanation:

• No. of mili equivalent of acid=50 x 0.4 = 20
• No. of mili equivalent of base = 50 x 0.2 = 10

Now, as the

Mili equivalent of acid > mili equivalent of base

Remaining mili equivalent of acid = 10 which is also equal to that of H+.

Normality of H+ =10/(50+50) = 0.1

So, pH = -log(N) = 1

Thus the pH of the solution is 1.

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The pH of a solution obtained by mixing 100 ml of 0.2 M CH3COOH with 100 ml of 0.2 M NaOH will be??(given pKa for CH3COOH =4.74 and log 2=0.301)  ?

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