Show that the median of a triangle divides it into two equal triangles of same area
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let in triangle
ABC AM be median
BM=MC(m is the mid point of BC)
angle AMB=angle AMC=90
AM=AM
therefore triangle ABM is congruent to Triangle ACM by RHS rule
therefore area of triangle ABM=area of triangle ACM
therefore median AM divide triangle ABC into two triangle of equal area
ABC AM be median
BM=MC(m is the mid point of BC)
angle AMB=angle AMC=90
AM=AM
therefore triangle ABM is congruent to Triangle ACM by RHS rule
therefore area of triangle ABM=area of triangle ACM
therefore median AM divide triangle ABC into two triangle of equal area
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