Question

Show that the operator is diagonal in its own basis.​

Answer 1

$\huge{\mathcal\red{♡Answer:}}$

In simple terms, we say that an operator is always diagonal in its own basis. This special form of the matrix representing the operator is similar to the special form that the eigenvectors ± take in this same representation—the eigenvectors are unit vectors in their own basis.

$<marquee>  ♥❤♥ Please follow me and mark as brainliest. ♥❤♥  </marquee>$