Question

Show that the points (-3,2), (-5,-5),(2,-3) and (4,4) are
the area of this rhombus.​

Answer 1

Answer:

hope it will help

Step-by-step explanation:

use the formula of distance

in (A,B),(B,C),(C,D), (A,D)

answer will be same in all

Answer 2

Answer:

Step-by-step explanation:

Hey there given 4 vertices ,

 A(-3,2),B(-5,-5) C(2,-3) and D( 4,4)

now ,

using distance formula ,

distance between AB = √(-5+3)² +(-5-2)² = √4 + 49 =√53,

distance between BC = √(2+5)²+(-3+5)² =√49+4 =√53, 

distance between CD = √(4-2)²+(4+3)² = √4 + 49 = √53,

and also ,

distance between AD =√(4+3)²+(4-2)² =√49+4= √53,

all sides are equal 

now check for the diagonals 

AC = √(2+3)²+(-3-2)²= √25+25 = √50

now Diagonal BD =√(4+5)²+(4+5)² =√81+81 = √162

All sides are equal but diagonals arent equal, hence, it is a rhombus.

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