Show that the points (-4,-7). (-1, 2), (8, 5) and (5, 4) taken in order are the vertices of a rhombus. And find its area
Answers
Answered by
1
Step-by-step explanation:
hlo mate here's your answer
Let the points are
A(−4,−7),B(−1,2),C(8,5),D(5,−4)
AB
=
(−1−(−4))
2
+(2−(−7))
2
=
2
3 2
=
90
= 3
10
BC
=
(8−(−1))
2
+(5−2)
2
=
2
9 2
=
90
= 3
10
CD
=
(5−8)
2
+(−4−(5))
2
=
2
3 2
=
90
= 3
10
DA
=
(−4−(5))
2
+(−7−(−4))
2
=
2
9 2
=
90
= 3
10
now ,
AC
=
(8−(−4))
2
+(5−(−7))
2
=
(12)
2
+(12)
2
=
144
=
12
2
BD
=
(5−(−1))
2
+(−4−2)
2
=
2
6 2
=
72
=
6
2
Since ,
AB=
CD=
BC=
DA,AC=
BD
so, it is rhombus.
Area of rhombus
=
2
1
×
12
2
×
6
2
=
72
I hope its help you mark as brainlist plz ok ok ok
Answered by
0
72 it is the answer
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