Show that the polynomial 9xsquare+6x+4 has no real zeroes
Answers
Answered by
0
Nature of roots os said by using Discriminant value
Discriminant=b^2-4ac=(6)^2-4(9)(4)= 36-144= -108
Discriminant<0 means no real zeroes
Hope this helps you
Mark as Brainliest answer please
Answered by
0
9 x^2+6x+4=0
it is in the form of a x^2+bx+c=0
a=9 b=6 c=4
discreminent= b^2-4ac
= (6)^2-4(9)(4)
= 36-144
= -108
b^2-4ac<0
:. 9x^2+6x+4=0 has no real roots
Similar questions