Math, asked by prasantadutta1431, 9 months ago

Show that the polynomial 9xsquare+6x+4 has no real zeroes

Answers

Answered by paidilokesh295
0

Nature of roots os said by using Discriminant value

Discriminant=b^2-4ac=(6)^2-4(9)(4)= 36-144= -108

Discriminant<0 means no real zeroes

Hope this helps you

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Answered by koushikj401
0

9 x^2+6x+4=0

it is in the form of a x^2+bx+c=0

a=9 b=6 c=4

discreminent= b^2-4ac

= (6)^2-4(9)(4)

= 36-144

= -108

b^2-4ac<0

:. 9x^2+6x+4=0 has no real roots

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