Show that the sides opposite to equal angles in a triangle are equal.
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Answered by
6
Answer:
just i took it from my book i read
ABC is a given triangle with, AB=AC.
To prove: Angle opposite to AB= Angle
opposite to AC (i.e) ∠C=∠B
Construction: Draw AD perpendicular to BC
∴∠ADB=∠ADC=90
o
Proof:
Consider △ABD and △ACD
AD is common
AB=AC
∴∠ADB=∠ADC=90
o
Hence ∠ABD=∠ACD
∠ABC=∠ACB
∠B=∠C. Hence the proof
Answered by
0
Answer:
proved Ab=Ac
Step-by-step explanation:
plz mark brainlist
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