Show that the speed of the electron in the second orbit of hydrogen like atom he is equal to speed of an electron in hydrogen atom.
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Velocity at nth orbit is v= (2.165 x10^6) x (Z/n)
actually v= (2( pi ^2)Km(e^2)Z )/(hn)
K= electrostatic constant
m= mass of electron
e= charge of electron
h= planks cnst
n= nth orbit
Z= atomic number
this simplifies to the top expression
so for 3rd orbit of hydrogen
v= (2.165x 10^ 6 )/ 3
v= x/3
actually v= (2( pi ^2)Km(e^2)Z )/(hn)
K= electrostatic constant
m= mass of electron
e= charge of electron
h= planks cnst
n= nth orbit
Z= atomic number
this simplifies to the top expression
so for 3rd orbit of hydrogen
v= (2.165x 10^ 6 )/ 3
v= x/3
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