Question

show that the square of odd positive integer can be of the form 6q+1 or 6q+3 for some integer q. plzzz solve ti.....

Answer 1

let a be any integer and b be 6. by EDL method a=6q+r , where 0<=r<6. r=0,1,2,3,4,5. if r=0,then a= 6q. if r=1,then a=6q+1. if r2,then a=6q+2. if r=3,then a=6q+3. if r=4,then a=6q+4. if r=5,then a=6q+5. a2=(6q)2=(36)2=6(6q) (use ( a+ b)=a2+b2+2ab use that formula for all.