show that x=1 is root of polynomial 2x^3-3x^2+7x-6
Answers
Answered by
1
Answer:
answer is 12
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Answered by
7
Answer:
x+1=0
x=0-1
x=-1
put -1 in place of x
2(-1)³-3(-1)²+7(-1)-6=0
-2-3-7-6=0
-18 =0
0=18
Step-by-step explanation:
hope it helps u my friend :)
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