Question

show that (x+4),(x-3) and (x-7) are factors of x^3-6x^2-19x+84.

Answer 1

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Answer 2

Answer:

Given factors are the true factor of equation.  

Step-by-step explanation:

Given : Factors (x+4),(x-3) and (x-7) of $x^3-6x^2-19x+84$

To find : Show that factors are true?

Solution :

We multiply the factor to find the equation if the equation is same as given equation then factors are true.

Equation is $(x+4)(x-3)(x-7)$

$=(x^2-3x+4x-12)(x-7)$

$=(x^2+x-12)(x-7)$

$=x^3+x^2-12x-7x^2-7x+84$

$=x^3-6x^2-19x+84$

Equations are same.

Therefore, Given factors are the true factor of equation.