show the derive of 2 equation of motion
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Second equation of motion is:- S = ut+1/2at^2
Derivation:-
We know that,
Average velocity = u+v/2..........eq. (i)
Distance travelled = Average velocity × time
S = v with bar × t..............eq. (ii)
Using eq. (i) and (ii), we obtain........
S = (u+v/2)×t
From equation (I) of motion i.e., v = u+at
Using it in equation (ii),
S = (u+at+u/2)×t
S = (2u+at/2)×t
S = 2ut+at^2/2
S = 2ut/2+1/2 at^2
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S = ut+1/2at^2.........Proved!
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