Question

express the complex number z=(3-2i) square/(1+i)cube in the form of A+iB​

Answer 1

Answer:

Step-by-step explanation:

(3-2i)^2/(1+i)^3

9-12i+4i^2/1+3i+3i^2+i^3

9-12i-4/1+3i-3-i

5-12i/-2+2i

5-12i*(-2-2i)/-2+2i*(-2-2i)

-10-10i+24i+24i^2/4-4i^2

-10-24+14i/8

-34+14i/8

-34/8+14i/8

-17/4+7i/4