Show the non-existence of helium molecule based on molecular orbital theory.
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Electronic configuration of He atom – 1s2
According Linear combination of atomic orbitals the He2 molecule electronic configuration is – σ1s2 σ*1s2
Thus there are equal number of electrons present in bondig molecular orbitals and anti-bonding molecular orbitals.
Bond order in He2 molecule = ½[number of electrons in bonding orbital- number of electrons in anti bonding orbital]
= ½[2-2]
= ½[0]
= 0
Thus there are Zero (0) number of bonds present between He atoms in He2 molecule.
Thus there is no existence of He2 (diatomic Helium)molecule.
According Linear combination of atomic orbitals the He2 molecule electronic configuration is – σ1s2 σ*1s2
Thus there are equal number of electrons present in bondig molecular orbitals and anti-bonding molecular orbitals.
Bond order in He2 molecule = ½[number of electrons in bonding orbital- number of electrons in anti bonding orbital]
= ½[2-2]
= ½[0]
= 0
Thus there are Zero (0) number of bonds present between He atoms in He2 molecule.
Thus there is no existence of He2 (diatomic Helium)molecule.
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