Question

Side of traingle are 17cm,19cmand22cm find it's area of triangle

Answer 1

Step-by-step explanation:

perimeter= 17+19+22 =58 cm

semi perimeter = 58/2=29

s-a = 29-17= 12

s-b =29-19= 10

s-c = 29-22 =7

area of the triangle = √s(s-a)(s-b)(s-c)

= √29×12×10×7

=√29×3×2×2×2×5×7

=2√6090 sq.cm