side of triangle are in ratio 12:17:25: and its perimeter is 540. find its area?
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Answered by
28
ratio of sides
12: 17:25
let them be
12x,17x, 25x respectively
perimeter of a triangle = sum of all sides
540 = 12x,17x, 25x
540 = 54x
x = 10
all sides measure
12x = 12×10 = 120
17x = 17× 10 = 170
25x= 25 × 10 = 250
it's semipetimeter = 540/2
= 270
using heron's formula area of the triangle =
root {(s)(s-a)(s-b)(s-c)}
where s is the semipetimeter and a,b,c
area the sides of the triangle.
root {( 270)(270-120)(270-170)(270-250)}
= 9000cm^2.
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Answered by
14
Let, 1st side =12x
2nd side=17x
3rd side=25x
The perimeter of triangle= (12x+17x+25x)
=54x
ATQ,
54x=540
or,x=10
the area is-
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