Question

sides of a triangle are 131/2 m, 11/8 m and 3/8 m. Find its perimeter.​

Answer 1

➤ Answer

• Perimeter of triangle => 67.25 m

➤ To Find

• The perimeter of triangle.

➤ Given

• Sides of triangle are 131/2m, 11/8m and 3/8m.

➤ Step By Step Explanation

Given that ⤵

• Sides of triangle are 131/2m, 11/8m and 3/8m.

We need to find the perimeter of the triangle.

So let's do it !!

Perimeter of triangle = Sum of all the sides.

$:\longmapsto\sf\cfrac{131}{2} + \cfrac{11}{8} + \cfrac{3}{8} \\ \\:\longmapsto\bf By \: taking \: L.C.M. \downarrow \\ \\:\longmapsto\sf \cfrac{(131 \times 4) + 11 + 3}{8} \\ \\ :\longmapsto\sf \cfrac{524 + 11 + 3}{8} \\ \\:\longmapsto\sf \cfrac{538}{8} \: m$

By reducing it to it's lowest term.

${\tt\longmapsto\cfrac{538}{8}\:\implies67.25m }$

Therefore perimeter of triangle => 67.25 m.

__________________________

Answer 2

Step-by-step explanation:

Given:

• The sides of the ∆

To Find:

• The perimeter of the ∆

Solution:

Formula Used-

Perimeter of a ∆= Sum of it's side

=131/2+11/8+3/8

=(524+11+3)/8

=538/8

=269/4cm ANS