Question

Using suitable identity find the value of (100 - 1)(100 + 1)

please answer fast
I'll mark you brainliest please help fast please fast with some steps​

Answer 1

Answer:

The value of (100.1)^2(100.1)

2

is equal to 10020.01.

Step-by-step explanation:

We have,

(100.1)^2(100.1)

2

To find, the value of (100.1)^2(100.1)

2

= ?

∴ (100.1)^2(100.1)

2

=(100+0.1)^2=(100+0.1)

2

Using the algebraic identity,

(a+b)^2=a^{2} +2ab+b^2(a+b)

2

=a

2

+2ab+b

2

Here, a = 100 and b = 0.1

= 100^2100

2

+ 2(100)(0.1) + 0.1^20.1

2

= 10000 + 200(0.1) + 0.01

= 10000 + 20 + 0.01

= 10020 + 0.01

= 10020.01

∴ The value of (100.1)^2(100.1)

2

= 10020.01

Thus, the value of (100.1)^2(100.1)

2

is equal to 10020.01.

Answer 2

Step-by-step explanation:

We know

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(100 + 1)(100 - 1)$

${100}^{2} - {1}^{2}$

$10000 - 1$

$9999$