silver has two naturally occurring isotopes, one of mass 107amu and other of mass 109amu. Find fraction of abundances for these two isotopes. the atomic mass is 107.8amu.
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Let fraction of 107Ag be x.
Therefore fraction of 109Ag is (1-x)
Now taking the weighted average, 107x + 109(1-x)=107.8 (given)
Thus, x=0.6 and (1-x)=0.4
Inform if wrong, approve if correct.
aliya97:
this is correct
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