Question

Simay’s age is 3 times as old as Meva’s age. Ayşe is 10 years older than Simay. If four years ago, Ayşe’s age was 8 less than twice the sum of the age of Simay and Meva . Find the present age of Simay

Answer 1

Answer:

present age of simay = 3x

3×3

9years

Answer 2

Step-by-step explanation:

let age of meva=x

age of simay =3x

age of ayse =3x+10

4years ago

age of meva =x-4

age of simay =3x-4

age of ayse=3x+10-4 =>3x+6

acc to problem

3x+6=2(x-4+3x-4)-8

3x+6=2(4x-8)-8

x=6

age of simay =3(6)

=18

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