Simple sum...for class 9 th standard I think but now my brain is not working ( do no. 5 sum only)...
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(a+b-c)2=a2 +b2+c-2(bc+ca-ab)
=314-(2×125)
=314-250
=64
Therefore,(a+b-c)=square root of +_64
=+_8
=314-(2×125)
=314-250
=64
Therefore,(a+b-c)=square root of +_64
=+_8
Aaryadeep:
right answer but wrong solution
if u please correct it:)
Plzz do it fast guyz i need proper sleep to restore my brain cause i just returned from an exam
solution incorrect but nice attempt.
Answered by
1
@
bc+ca-ab=125, a²+b²+c²=314
(a+b+(-c))²=a²+b²+(-c)²+2(ab-bc-ca)
(a+b-c)²=a²+b²+c²-2(-ab+bc+ca)
(a+b-c)²=314-2×125
(a+b-c)²=64=(±8)²
a+b-c=±8
@:-)
bc+ca-ab=125, a²+b²+c²=314
(a+b+(-c))²=a²+b²+(-c)²+2(ab-bc-ca)
(a+b-c)²=a²+b²+c²-2(-ab+bc+ca)
(a+b-c)²=314-2×125
(a+b-c)²=64=(±8)²
a+b-c=±8
@:-)
Thanks
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