Question

Simplify....................

Answer 1

$(1^3+2^3+3^3+4^3+5^3)^{-\frac{1}{2}}$

$=(1+8+27+64+125)^{-\frac{1}{2}}$

$=(225)^{-\frac{1}{2}}$

$=\frac {1}{225^{\frac{1}{2}}}$

$=\frac {1}{\sqrt{225}}$

$=\frac {1}{15}$

Hence final answer is $\frac {1}{15}$.

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ that:\\\\(\ 1^3 \ + \ 2^3 \ + \ 3^3 \ + \ 4^3 \ +5^3)^{\ - \frac{1}{2}} \\\\\ Find: \\\\\ Sum \ = \ ?$

$\ Solve:$

$\therefore \ a^3= a\times \ a\times \ a\\\\\\\because \\\\\ 1^3 =\ 1\times \ 1 \times 1 \ = \ 1\\\\2^3\ = \ 8\\\\3^3\ = \ 27\\\\4^3\ = \ 64\\\\5^3 \ = \ 125$

$\rightarrow (\ 1^3 \ + \ 2^3 \ + \ 3^3 \ + \ 4^3 \ +5^3)^{\ - \frac{1}{2}} \\\\\rightarrow (\ 1 \ + \ 8 \ + \ 27 \ + \ 64 \ +125)^{\ - \frac{1}{2}} \\\\\rightarrow (225)^{\ - \frac{1}{2}} \\\\\rightarrow {\frac{1}{225}}$

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