Math, asked by SapnaAggarwal, 1 year ago

Simplify by rationalising the denominator 7+3√5/7-3√5

Answers

Answered by aashi2203
18
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Answered by OoINTROVERToO
2

 \bf \frac{7 + 3  \sqrt{5} }{7 - 3 \sqrt{5} }  \\  \\  \bf \frac{7 + 3  \sqrt{5} }{7 - 3 \sqrt{5} }  \times  \bf \frac{7 + 3  \sqrt{5} }{7  +  3 \sqrt{5} }  \\  \\  \bf \frac{(7 + 3  \sqrt{5} )^{2}  }{(7)^{2}  - (3 \sqrt{5} )^{2} }  \\  \\  \bf \frac{49 + 45 + 42 \sqrt{5} }{49- 45 }  \\  \\  \bf \frac{94+ 42\sqrt{5} }{4}  \\  \\ \bf \frac{47+ 21\sqrt{5} }{2}

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