simplify ( sec A + tan A ) ( 1- sin A)
srana80:
the simplest ans is cos a
yes it is that I have brought.
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( sec A + tan A ) ( 1 - sin A )
= 1/cos A + sin A/cos A - sin A . 1/cos A - sin A . sin A / cos A
= 1/ cos A + sin A /cos A - sin A / cos A - sin^2 A / cos A
= sec A - tan A + sec A
= 2 sec A - tan A
= 2 × 1/ cos A - sin A / cos A
= 2 - sin A / cos A
= 1/cos A + sin A/cos A - sin A . 1/cos A - sin A . sin A / cos A
= 1/ cos A + sin A /cos A - sin A / cos A - sin^2 A / cos A
= sec A - tan A + sec A
= 2 sec A - tan A
= 2 × 1/ cos A - sin A / cos A
= 2 - sin A / cos A
hey! is it right?
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