Question

sinA, cosA, and tanA are in GP, then cos(cube)A + cos(square)A = ?

Answer 1

the common r in between the gp are equal ..so u can use that

Answer 2

Answer:

1

Step-by-step explanation:

the equation that is applicable in gp is

b^2 = a*c

here we have cosA as b

therefore,

cos^2A = sinA*tanA

             = sinA*sinA/cosA              (writing tan as sinA/cosA)

we get :

cos^3A= sin^2A

thus,

substituting the value in the question , we get :

sin^2A + cos^2A  = 1

thus

the answer is 1.