simplify the equation
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Let
a= (x^3-y^3)^3
b= (y^3-z^3)^3
c= (z^3-x^3)^3
if a+b+c=0
then a^3+b^3+c^3=3abc
Using this formula in the given equation, we get
= 3(x^3-y^3)(y^3-z^3)(z^3-x^3) / 3(x-y)(y-z)(z-x)
= (x-y)(x^2+y^2+xy)(y-z)(y^2+z^2+yz)(z-x)(z^2+x^2+zx) / (x-y)(y-z)(z-x)
= (x^2+y^2+xy)(y^2+z^2+yz)(z^2+x^2+zx)
Hope you understood :D
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