Question

Simplify the following [2/9÷3/5] ÷6/5of [3/5×2/15]

Answer 1

Answer:

(2/9÷3/5)÷6/5  of (3/5  × 2/15)

Step-by-step explanation:

(2/9÷3/5)÷6/5  of (3/5  × 2/15)

= (2/9×5/3)÷6/5  × (3/5  × 2/15)

=  (2/9×5/3)÷ (6/5  ×3/5  × 2/15)

= (2/9×5/3)× (5/6  ×5/3  × 15/2)

= (2/9×5/3)× ((5×5×5)/(6×2)  )

= ((2×5×125)/(9×3×12)  )

= (625/162  )

= 3  139/162

Answer 2

The answer is $\frac{625}{162}$.

Step-by-step explanation:

According to the given information, the problem is,  [2/9÷3/5] ÷6/5of [3/5×2/15].

Now, this can be solved with the help of the BODMAS rule where terms related with the bracket is solved first, then terms related with of is solved next, next terms related with division is solved next, then terms related with   Multiplication is solved next, next terms related with addition is solved next, and finally terms related with subtraction is solved.

Here, this problem can be solved with the help of the BODMAS rule.

Now,

[2/9÷3/5] ÷6/5of [3/5×2/15].

Here, first terms inside the brackets are solved.

[2/9*5/3] ÷6/5of [2/25].

=[10/27] ÷6/5of [2/25].

Now, terms with the of is solved.

[10/27] ÷6/5of [2/25].

=[10/27] ÷[12/125]

=625/162.

Hence, the answer is $\frac{625}{162}$.

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