Math, asked by StarTbia, 1 year ago

Simplify the following into their lowest forms.

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Answered by Robin0071
0
Solution:-

given by:-
 \frac{(x - 8)( {x}^{2}  + 5x - 50)}{(x + 10)( {x}^{2} - 13x + 40) }  \\  \frac{(x - 8)( {x}^{2} + 10x - 5x - 50) }{(x + 10)( {x}^{2}  - 8x + 5x + 40)}  \\  \frac{(x - 8)(x(x + 10) - 5(x + 10))}{(x + 10)(x(x - 8) - 5(x - 8))}  \\  \frac{(x - 8)(x + 10)(x - 5)}{(x + 10)(x - 8)(x - 5)}  \\  \frac{1}{1}  = 1 \: ans
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Answered by rohitkumargupta
0
HELLO DEAR,
 \mathit{\frac{(x - 8)( {x}^{2} + 5x - 50)}{(x + 10)( {x}^{2} - 13x + 40) } } \\ \\  \mathit{\frac{(x - 8)( {x}^{2} + 10x - 5x - 50) }{(x + 10)( {x}^{2} - 8x + 5x + 40)} } \\ \\  \mathit{\frac{(x - 8)(x(x + 10) - 5(x + 10))}{(x + 10) [ x(x - 8) - 5(x - 8) ]} } \\ \\ \mathit{\frac{(x - 8)(x + 10)(x - 5)}{(x + 10)(x - 8)(x - 5)}}  \\ \\  \mathit{\frac{1}{1} = 1 }


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