simplify this question
yh vala agar sahi answer diya to agli bar Points bada ke question puchunga ok
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Answer:
(x+y)(y+z)(z+x)
Step-by-step explanation:
Taking first Numerator
N=(x²-y²)³+(y²-z²)³+(z²-x²)³
Here (x²-y²)+(y²-z²)+(z²-x²)=0
so N=(x²-y²)³+(y²-z²)³+(z²-x²)³=3(x²-y²)(y²-z²)(z²-x²)----------------(1)
similarly Denominator
D=(y-z)³+(z-x)³+(x-y)³=3(y-z)(z-x)(x-y)
So fraction=N/D=3(x²-y²)(y²-z²)(z²-x²)/3(y-z)(z-x)(x-y)
=(x+y)(y+z)(z+x)
Anonymous:
ok dear thanks
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