Math, asked by Boby9560, 1 year ago

simplify this question
yh vala agar sahi answer diya to agli bar Points bada ke question puchunga ok​

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Answers

Answered by Anonymous
1

Answer:

(x+y)(y+z)(z+x)

Step-by-step explanation:

Taking first Numerator

N=(x²-y²)³+(y²-z²)³+(z²-x²)³

Here (x²-y²)+(y²-z²)+(z²-x²)=0

so N=(x²-y²)³+(y²-z²)³+(z²-x²)³=3(x²-y²)(y²-z²)(z²-x²)----------------(1)

similarly  Denominator

D=(y-z)³+(z-x)³+(x-y)³=3(y-z)(z-x)(x-y)

So fraction=N/D=3(x²-y²)(y²-z²)(z²-x²)/3(y-z)(z-x)(x-y)

=(x+y)(y+z)(z+x)


Anonymous: ok dear thanks
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