simplify (x+3)^3 +(x-3)^3 using identity
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2 (x^3+3^3) it is the answer
Nehakadam:
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Hey !!!
we know a identity
(a + b )³ = a³ + b³ + 3a²b + 3ab²
and , ( a - b ) ³ = a³ - b³ - 3a²b + 3ab²
From this identity ..
we can write .. this equation like that
(x + 3)³ + (x - 3)³
= x³ + 3³ + 3×x²×3 + 3×3²×x + { x³ - 3³ - 3x²×3 + 3×3²×x
= x³ + 27 + 9x² + 27x + x³ - 27 - 9x² + 27x
= x³ + x³ + 27x + 27x
= 2x³ + 54x
= 2x ( x²+ 27 )
or, 2x ( x² + 3³)
hence here factorise
******************************
Hope it helps you ;!!
@Rajujumar111
we know a identity
(a + b )³ = a³ + b³ + 3a²b + 3ab²
and , ( a - b ) ³ = a³ - b³ - 3a²b + 3ab²
From this identity ..
we can write .. this equation like that
(x + 3)³ + (x - 3)³
= x³ + 3³ + 3×x²×3 + 3×3²×x + { x³ - 3³ - 3x²×3 + 3×3²×x
= x³ + 27 + 9x² + 27x + x³ - 27 - 9x² + 27x
= x³ + x³ + 27x + 27x
= 2x³ + 54x
= 2x ( x²+ 27 )
or, 2x ( x² + 3³)
hence here factorise
******************************
Hope it helps you ;!!
@Rajujumar111
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