Question

the sum of two digit number and the number obtained by reversed the order of its digit is 121 and the two digit differ by 3 .find the number

Answer 1

your answer is here. Are you understand

Answer 2

Answer:

Step-by-step explanation:

Let the ones digit be x and tens digit be y

Required number is 10 * x + y

According to the question,

(10 * x + y) + (10 * y + x) = 121

11 * x + 11 * y = 121

x + y = 121/11

x + y = 11...................................i

and if x > y

x-y = 3.......................................ii

and if x < y

y - x = 3.....................................iii

Adding i and ii we get

2 x = 14

x = 14/2 =7

and y = 4 so the required number be 10 * 7 + 4 = 74

Adding i and iii we get,

2 y = 14

y = 7

and x = 7

the required number be 10 * 4 + 7 = 47

Since it is not given that which digit is greater, so the two possible numbers are 74 or 47.