Question

simplify. (x+y+z) ^2- (x-y-z) ^2​

Answer 1

Answer:

Something jumps out at me; notice that the last three terms are the same as each other, with x , y , and z swapped around. It’s easier to see if you notice (−x+y−z)2=(x−y+z)2 .

So the result should be completely symmetrical. Count the terms with x and the coefficients for the others will be the same.

You get 4 versions of x2 , and 2−2−2+2=0 versions of xy - so there must be four of each square, and no cross terms. The result must be 4(x2+y2+z2) .

Step-by-step explanation:

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Answer 2

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