simplify:xy[x+y](1/x-1/y)+2x/y]
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Answered by
38
xy[(x+y)(1/x-1/y)+2x/y]
=> xy[(x+y)(y-x)/xy + 2x/y]
=> xy[(x²-y²)/xy+2x/y]
(a-b)(a+b) = a²-b²
=> xy[(x²-y²)/xy+x(2x)/xy]
=> xy [(x²-y²+2x²)/xy]
=> xy [(x²+y²)/xy]
=> xy and xy got cancelled out so, our answer is
=> x²+y²
hope this helps
any confusion then inbox me
=> xy[(x+y)(y-x)/xy + 2x/y]
=> xy[(x²-y²)/xy+2x/y]
(a-b)(a+b) = a²-b²
=> xy[(x²-y²)/xy+x(2x)/xy]
=> xy [(x²-y²+2x²)/xy]
=> xy [(x²+y²)/xy]
=> xy and xy got cancelled out so, our answer is
=> x²+y²
hope this helps
any confusion then inbox me
Answered by
0
Answer:
x^2+y^2
Step-by-step explanation:
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