Question

Sin -1 x + sin -1 y = pi/2... then find dy/dx

Answer 1

sin⁻¹x+sin⁻¹y=π/2
Differentiating both sides w.r.t x we get,
1/√(1-x²)+1/√(1-y²)($\frac{dy}{dx}$)=0
or, 1/√(1-y²)($\frac{dy}{dx}$)=-1/√(1-x²)
or, $\frac{dy}{dx}$={-1/√(1-x²)}/{1/√(1-y²)}
or, $\frac{dy}{dx}$=-√(1-y²)/(1-x²)