Math, asked by ira96, 1 year ago

sin(-11pi/3),find the values of the trigonometric functions.

Answers

Answered by msaikarthik
14
-11pie/3 value is equal to
-11multiplied by 180 divided by 3
the answer will be -660
sin(-660)
sin(0-660)
sin(360-660)
sin(-300)
sin(0-300)
sin(360-300)
sin60degrees
the answer will be root of 3/2

ira96: thanks
msaikarthik: welcome
ira96: aap ka naam kya ha
Answered by rakeshmohata
13
Hope u like my process
=====================
For any angles,

 = > 0 °= 360 °= 2\pi = 4\pi = 2\pi \times n
Where : n = 1,2,3,....

Now,

 = > \sin( - \frac{11\pi}{3} ) \\ \\ = \sin(0 - \frac{11\pi}{3} ) \\ \\ = \sin(4\pi - \frac{11\pi}{3} ) \\ \\ = \sin( \frac{12\pi - 11\pi}{3} ) = \sin( \frac{\pi}{3 } ) \\ \\ = \frac{ \sqrt{3} }{2}
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer

Proud to help you
Similar questions