Math, asked by akashsri931, 1 year ago

sin 18° .cos 36° - sin75° .cos75°=?

Answers

Answered by Anonymous
9
Hey friend ..!! here's your answer
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 \sin(18)  \times  \cos(36)  -  \sin(75)  \times  \cos(75)  \\  \\  \frac{1}{ \cos(18) }  \times  \cos(36)  -  \frac{1}{cos(75)}  \times  \cos(75 \\  \\ 2 -1   \\  \\ 1


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#Hope its help
Answered by Ashishkumar098
9
ʜᴇʏᴀ!!

ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ

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sɪɴ 18° × ᴄᴏs 36° - sɪɴ 75° × ᴄᴏs 75° 

= 1 / ᴄᴏs 18° × ᴄᴏs 36° - 1 / ᴄᴏs 75° × ᴄᴏs 75°

= 2 - 1

= 1

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ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)

# ᴅᴇᴠɪʟ ᴋɪɴɢ

Anonymous: mere answer k saath...
Ashishkumar098: Matlab.. 0_o
Anonymous: mtlb....dono bhai ne ek hi answer dia h....accha h
Anonymous: :)
Ashishkumar098: achhaaaa ji
Ashishkumar098: ha ay tho ha
Ashishkumar098: ^_^
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