sin^{2} x + sin^{2} y = 1 dy/dx ज्ञात कीजिए
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dy/dx = -Sin2x/Sin2y यदि Sin²x + Sin²y = 1
Step-by-step explanation:
dy/dx ज्ञात कीजिए
Sin²x + Sin²y = 1
=> 2SinxCosx + 2SinyCosydy/dx = 0
=> 2SinyCosydy/dx = - 2SinxCosx
=> dy/dx = - 2SinxCosx/2SinyCosy
=> dy/dx = -Sin2x/Sin2y
और अधिक जानें :
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